Calculate the freezing point and the boiling point of a saturated solution of Li₂CO₃. The solubility of lithium carbonate is 0.72 g per 100 g of water at 100 degrees C.

Answer:

We need to begin by calculating the molality of the saturated Li₂CO₃ solution.

We know the molality of the Li₂CO₃ solution, but we need to consider that Li₂CO₃ is a strong electrolyte. Determine the number of particles Li₂CO₃ forms when dissolved in water.

Li₂CO₃(s) -H₂O--> 2Li⁺(aq) + CO₃^2-(aq)

Every mol Li₂CO₃ that dissolves produces 3 mol of particles.

Calculate the change in freezing point and check your answer here.