Calculate the mass of SbI
_{3}
formed when 1.20 g of Sb react with 2.40 g of I
_{2}
, according to the equation,
2Sb
_{(s)}
+ 3I
_{2(s)}
---> 2SbI
_{3(s)}
Solution:
To begin this problem we need to build the table.
In this table I decided to start with Sb. If you started with I
_{2}
your
table will look like;
(mol reactant Sb
_{}
)
_{o}
(mol reactant I
_{2}
)
_{required}
(mol reactant I
_{2}
)
_{o}
Conclusion
Now complete the table. When you have the calculations complete
check what I calculated
.